Quiz Class 10th Math Testing

Q1. If the HCF of two numbers is 9 and their LCM is 360. If one number is 45, what is the second number?

(यदि दो संख्याओं का HCF 9 है और उनका LCM 360 है। यदि एक संख्या 45 है, तो दूसरी संख्या क्या होगी?)

A) 36
B) 72
C) 81
D) 90

Correct Answer: B) 72

Q1 Solution

Using the formula:

$$
\text{HCF} \times \text{LCM} = \text{Product of two numbers}
$$

Given:

$$
\text{HCF} = 9
$$

$$
\text{LCM} = 360
$$

One number:

$$
45
$$

Let the second number be:

$$
x
$$

Applying the formula:

$$
9 \times 360 = 45 \times x
$$

$$
x = \frac{9 \times 360}{45}
$$

$$
x = \frac{3240}{45}
$$

$$
x = 72
$$

Correct Answer: B) 72


Q2. What is the value of $$\sin 30^\circ + \cos 60^\circ$$?

($$\sin 30^\circ + \cos 60^\circ$$ का मान क्या है?)

A) 0
B) 1/2
C) 1
D) $$\sqrt{3}$$

Correct Answer: C) 1

Q2 Solution

From trigonometric values:

$$
\sin 30^\circ = \frac{1}{2}
$$

$$
\cos 60^\circ = \frac{1}{2}
$$

Adding the values:

$$
\frac{1}{2} + \frac{1}{2}
$$

$$
= \frac{1+1}{2}
$$

$$
= \frac{2}{2}
$$

$$
= 1
$$

Correct Answer: C) 1


Q3. The roots of the quadratic equation $$x^2 – 3x – 10 = 0$$ are:

(द्विघात समीकरण $$x^2 – 3x – 10 = 0$$ के मूल (roots) क्या हैं?)

A) 5, -2
B) -5, 2
C) 5, 2
D) -5, -2

Correct Answer: A) 5, -2

Q3 Solution

Given equation:

$$
x^2 – 3x – 10 = 0
$$

Factorizing:

$$
x^2 – 5x + 2x – 10 = 0
$$

Grouping terms:

$$
x(x-5) + 2(x-5) = 0
$$

Taking common factor:

$$
(x-5)(x+2)=0
$$

Therefore:

$$
x-5=0
$$

or

$$
x+2=0
$$

So,

$$
x=5
$$

and

$$
x=-2
$$

Correct Answer: A) 5, -2


Q4. The 11th term of the AP: -3, -1/2, 2, … is:

(समान्तर श्रेणी (AP): -3, -1/2, 2, … का 11वाँ पद क्या है?)

A) 28
B) 22
C) -38
D) -48

Correct Answer: B) 22

Q4 Solution

First term:

$$
a = -3
$$

Second term:

$$
-\frac{1}{2}
$$

Common difference:

$$
d = -\frac{1}{2} – (-3)
$$

$$
d = -\frac{1}{2} + 3
$$

$$
d = \frac{5}{2}
$$

Formula for nth term:

$$
a_n = a + (n-1)d
$$

For 11th term:

$$
a_{11} = -3 + (11-1)\times\frac{5}{2}
$$

$$
= -3 + 10 \times \frac{5}{2}
$$

$$
= -3 + 25
$$

$$
= 22
$$

Correct Answer: B) 22


Q5. A tangent to a circle intersects it in how many point(s)?

(एक वृत्त की स्पर्श रेखा उसे कितने बिन्दुओं पर प्रतिच्छेद करती है?)

A) 0
B) 1
C) 2
D) Infinite (अनंत)

Correct Answer: B) 1

Q5 Solution

A tangent touches a circle at exactly one point.

Therefore:

$$
\text{Number of intersection points} = 1
$$

Correct Answer: B) 1

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